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3x^2=-4.5x-1
We move all terms to the left:
3x^2-(-4.5x-1)=0
We get rid of parentheses
3x^2+4.5x+1=0
a = 3; b = 4.5; c = +1;
Δ = b2-4ac
Δ = 4.52-4·3·1
Δ = 8.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{8.25}}{2*3}=\frac{-4.5-\sqrt{8.25}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{8.25}}{2*3}=\frac{-4.5+\sqrt{8.25}}{6} $
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